Universal Cup Judging System

Universal Cup

Time Limit: 2.0 s Memory Limit: 1024 MB Total points: 100 Hackable ✓
Statistics

There are $N + 1$ kinds of food in total: $N$ kinds of food numbered $1, 2, \dots, N$, and water jelly. For $i = 1, 2, \dots, N$, the sweetness of food $i$ is $A_i$ and its spiciness is $B_i$. The sweetness of water jelly is $0$ and its spiciness is $0$.

UTPC-kun first eats water jelly, then eats foods $1, 2, \dots, N$ exactly once each in any order, and finally eats water jelly again.

UTPC-kun's happiness is $0$ immediately after eating the first water jelly. After that, every time he eats a food, his happiness changes as follows:

  • Let $a$ and $b$ be the sweetness and spiciness of the food he is currently eating, and let $a'$ and $b'$ be the sweetness and spiciness of the food he ate immediately before. His happiness increases by $\max(a - a', b - b')$. (The increase in happiness can be negative.)

Find the maximum possible final happiness of UTPC-kun by choosing the optimal order to eat foods $1, 2, \dots, N$.

Input

The input is given in the following format:

N
A_1 B_1
A_2 B_2
:
A_N B_N
  • All input values are integers.
  • $1 \le N \le 5 \times 10^5$
  • $0 \le A_i, B_i \le 10^9$

Output

Print the answer on a single line.

Examples

Sample Input 1

4
1 4
3 1
2 3
3 4

Sample Output 1

6

Sample Input 2

3
1 2
2 1
1 2

Sample Output 2

3

Sample Input 3

6
3 1
4 1
5 9
2 6
5 3
5 8

Sample Output 3

18

Note

In the first example, one optimal order to eat the foods is $1, 2, 3, 4$. In this case, UTPC-kun's happiness changes as follows after he finishes eating the first water jelly:

  • Eats food $1$: His happiness increases by $\max(1 - 0, 4 - 0) = 4$, becoming $4$.
  • Eats food $2$: His happiness increases by $\max(3 - 1, 1 - 4) = 2$, becoming $6$.
  • Eats food $3$: His happiness increases by $\max(2 - 3, 3 - 1) = 2$, becoming $8$.
  • Eats food $4$: His happiness increases by $\max(3 - 2, 4 - 3) = 1$, becoming $9$.
  • Eats water jelly: His happiness increases by $\max(0 - 3, 0 - 4) = -3$, becoming $6$.

Editorials

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